موضوع مناقشة واجبات Phys102 للترم 112

العااااااااالم ساحبيييييييين
وانا معاكم 1-3

 

1. 112-Q1-Ch18-Lec02 (Points: 1) The energy given off as heat by 307 g of an alloy as it cools through 80.6 o C raises the temperature of 307g of water from 29.2 o C to 64.3 o C. What is the specific heat of the alloy (in cal/g. o C)?

Answer upto 2 decimal places.

Answer

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2. 112-Q2-Ch18-Lec02 (Points: 1) A heat of transformation of a substance is:

1. the energy per unit mass absorbed as heat during a phase transformation

2. the energy released as heat to raise the temperature of 1g of water by 1 degree C.

3. the energy absorbed as heat during a phase transformation

4. the energy absorbed as heat to raise the temperature of 1kg of water by 1 kelvin

5. the energy absorbed as heat to raise the temperature of 1g of water by 1 degree C.

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3. 112-Q3-Ch18-Lec02 (Points: 1) How many calories are required to change 7.9 gram of 0 o C ice to 100 o C steam? The latent heat of fusion is 80 cal/g and the latent heat of vaporization is 540 cal/g. The specific heat of water is 1.00 cal/g.K.

Answer

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i solved the questions but q1 was wrong


here are the solutions for Q2 & Q3


good luck


answer Q2 is : the energy per unit mass absorbed as heat during a phase transformation


answer Q3 :
mass *80 + mass *defrence T + mass * 540

you can see the solution down

 

Jump to Navigation Frame
Title: Ch18-Lec0
Total score: 3/3 = 100% Total score adjusted by 0.0 Maximum possible score: 3

1. 112-Q1-Ch18-Lec02

The energy given off as heat by 213 g of an alloy as it cools through 61.6 oC raises the temperature of 213g of water from 16.3 oC to 67.0 oC. What is the specific heat of the alloy (in cal/g. oC)?
Answer upto 2 decimal places.

Student Response Value
Answer: 0.82 100%
Score: 1/1

2. 112-Q2-Ch18-Lec02

A heat of transformation of a substance is:
Student Response Value Feedback
1. the energy absorbed as heat to raise the temperature of 1g of water by 1 degree C.
2. the energy per unit mass absorbed as heat during a phase transformation 100%
3. the energy absorbed as heat during a phase transformation
4. the energy absorbed as heat to raise the temperature of 1kg of water by 1 kelvin
5. the energy released as heat to raise the temperature of 1g of water by 1 degree C.
Score: 1/1

3. 112-Q3-Ch18-Lec02

How many calories are required to change 3.0 gram of 0 oC ice to 100 oC steam? The latent heat of fusion is 80 cal/g and the latent heat of vaporization is 540 cal/g. The specific heat of water is 1.00 cal/g.K.
Student Response Value
Answer: 2160 100%
Score: 1/1
السؤال الأول جوابه:من المعادله Q=Cm(T2-T1)
C of water=1
T2-T1 of aloy = 61.6
1*213*(67-16.3)=C*213*61.6
الباقي معروف من الي حله قبلي

 

Solution Ch18-Lec02

Q1: The energy given off as heat by 846 g of an alloy as it cools through 40.7 oC raises the temperature of 846g of water from 38.7 oC to 57.3 oC. What is the specific heat of the alloy (in cal/g. oC)?
Answer upto 2 decimal places.

the answer in the picture

Q2: A heat of transformation of a substance is:

the energy per unit mass absorbed as heat during a phase transformation

Q3: How many calories are required to change 1.9 gram of 0 oC ice to 100 oC steam? The latent heat of fusion is 80 cal/g and the latent heat of vaporization is 540 cal/g. The specific heat of water is 1.00 cal/g.K.

the answer in the picture

http://www.stkfupm.com/vb/attachment.php?attachmentid=7628&stc=1&d=1329575634

الحلول بإذن الله صحيحة مية في المية لأني أخذت 3\3
ومانبغى إلا دعواتكم لنا بـ A+
وبرضو الشباب الي فوق ماقصروا ، يعطيهم العافية

 

حل السؤال الأول .. والله يوفقنا وإياكم

 

مشكورين يحابيب

 

للي حاب يتأكد ، إضغط على الصورة للتكبير

 

يعطيكم العافية 3/3

 

فالكم الفل مارك

 

شادين حيلكم هالفصل يا شباب ما شاء الله

ذاك الفصل كان النشاط مو لهناك اما الحين توب التوب

يعطيكم العافية وفالكم التوفيق

 

Solution Ch18-Lec3

Q1: According to the first law of thermodynamics, applied to a gas, the increase in the
internal energy during any process:

equals the heat input plus the work done on the gas

Q2: A system can be taken from state i to state f along two different paths path1 and path2,
along path1 Q = 48.5cal and W = 25.5 Cal. Along path 2, Q = 43.1 cal. what is W along path 2?
Answer in calories.

the answer :
http://www.stkfupm.com/vb/attachment.php?attachmentid=7642&stc=1&d=1329668325 from this formula
since the internal energy in path 1 equals the internal energy in path 2 so,
http://www.stkfupm.com/vb/attachment.php?attachmentid=7643&stc=1&d=1329668325
http://www.stkfupm.com/vb/attachment.php?attachmentid=7644&stc=1&d=1329668325

Q3: The figure below shows three different paths (a, b, and c) on a p-V diagram along which a gas can be taken from state i to state f. Rank the paths according to the magnitude of the energy transferred as heat Q between the gas and its environment

http://www.stkfupm.com/vb/attachment.php?attachmentid=7645&stc=1&d=1329668434

the answer is : c, a, b

وبإذن الله إن الحلول صحيحة وأي سؤال أنا حاضر
وفي النهاية مانبي إلا دعواتكم لنا بالـ A+

 

يا اخوي السؤال الاخير .. الحين q-w ثابت لكل بروسيس من الثلاثه صح و لا لا
اذا كان صح فمعناته انك عاكس الاجابة ولا انا غلطان

 

يالغالي بداية فكرة السؤال هذا موجودة في التشيك بوينت
لكن عشان توضح لك الفكرة
في كل المسارات التغير في الطاقة متساوي الي هو delta E
فيعني لما إنت تزيد قيمة الـ W لازم تزيد قيمة الـ E عشان تبقى قيمة التغير في الطاقة متساوية
فبكذا أكبر شيء عندنا c ثم a ثم b

 

Thanx

 

اممممم
هل من جديد ؟

حل السؤال الثالث لـ king of net ؟ صحيح اعتمد عليه ولا احد عنده حل غير ؟

 

ياخوان ندري ان جواب السؤال الثاللث c,a,b فسروا الجواب هل صحيح ان اقول نرتبها على حسب المساحه مثل work

 

يمكن ال w يمثل بالarea under graph

كلامك سليم يا أبو مسفر

 

شباب السستم هنا معزوووول صح ؟؟ اذا كان مزول فمعنى ان q لازم تسساوي w علشششششششان delta E
تسسسسسساوي صفر صح علي ولا خرااااط ههههههههههه

 

؟؟؟؟